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Finding focus of an arc mathematically

oldfox

Alibre Super User
If it is not possible to generate a "tangent arc" using AlibreScript, then I need help with the formula to find the focus of the arc. I want to be able to use a script to generate the arc. Start and end points are known. The arc
must be tangent to the line on the left.
AddArc(Center,Start,End)

Thanks.
 

Attachments

  • Focus of arc sketch.AD_PRT
    234 KB · Views: 2

idslk

Alibre Super User
Hello Chris,

which points are given, which lines are given, are the lines under an certain angle, is the radius of the arc fixed...
Can you list some additional information refering to "your" sketch (see picture. I've added labels and the 2 blue lines 1+3)

upload_2019-6-30_18-14-33.png


Regards
Stefan
 

oldfox

Alibre Super User
Hi Stefan, thanks for the reply. My math just isn't up to this.

P5 is the Unknown and is needed.

Given: Points - Origin, P1, P2, and P8 is optional
Line 2 (Any length from P1)

Not needed but could be used:
Points - P3, P4, P8

Not needed:
Points - P6, P7
Lines - 1, 3, 4, 5

Lines 4 and 5 were only for "offset" construction and could be reference lines only.
I'm not sure if a Tangent Arc will work with a reference line or not.

Needed:
XY points - P1, P2, Origin
Line for Tangent Arc (line 2)

All lines are parallel with axes. No angles.

The arc radius will be determined by points 1 and 2 and tangent to line 2. Point 1 is the start point. Just like Alibre Design does it.
**********************************************
For a script I would only be using numbers for coordinates and the formula for POINT 5.

If I'm still not clear, just ask more.

Thanks again.
 
Hi Stefan, thanks for the reply. My math just isn't up to this.

P5 is the Unknown and is needed.
Hi Chris -- OK, I assume that you know the Coordinate values for P1 and P2. I will define these as P1 = (X1,X2) and P2 = (X2,Y2) -- OK? Thus the3 Line from P1 to P2 has the Slope of (Y2-Y1)/(X2-X1), right? The Midpoint between P1 to P2 (PM1-2) has the value PM1-2 = ((X2+X1)/2,(T2+Y1)/2). Right? The Slope of the Counterpoint Defining Line is (-1/((Y2-Y1)(X2-X1)) -- Correct? Now you can define the Equation of the Counterpoint Defining Line merely by finding the "Y intercept value." Knowing the Equation of the Counterpoint Defining Line and the Coordinate Values for P1 or P2 calculating the Centerpoint Value should be nigh unto trivial. Right?
 

idslk

Alibre Super User
Hello Chris,

can you draw what you want to get into a sketch including the contraint symbols and post a picture of that?

Regards
Stefan
 

oldfox

Alibre Super User
Hi Stefan,
Here's the part with, I hope, all of the information needed to see what I need. If you need more, ask for specific things and I'll get it to you.
Thanks,
Chris
 

Attachments

  • Focus of arc sketch.AD_PRT
    337 KB · Views: 6

idslk

Alibre Super User
Hello Chris,

a short picture with variable names and a formula:
upload_2019-6-30_21-5-12.png

in a spreadsheet...

upload_2019-6-30_21-5-0.png

Hope this helps;)

Regards
Stefan
 

oldfox

Alibre Super User
Hope this helps;)

Hi Stefan,
Completely understood. That's exactly what I needed. "The formula". Thank you so very much.
It calculates out to 6 places mm compared to AD's Measure tool.
Plenty good enough for me.
Are your letter variables German? (H, S, R) Radius I get but not H and S.
 
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